Notes: `y = cot^2(sin( theta))` Find the derivative of the function.

$\displaystyle{y}'=$
d/(d(theta))cot^2(sin(theta))

$\displaystyle={2}{\cot{{\left({\sin{{\left(\theta\right)}}}\right)}}}\cdot\frac{{d}}{{{d}{\left(\theta\right)}}}$
[cot(sin(theta))]

$\displaystyle={2}{\cot{{\left({\sin{{\left(\theta\right)}}}\right)}}}\cdot{\left(-{{\csc}}^{{2}}{\left({\sin{{\left(\theta\right)}}}\right)}\right)}\cdot\frac{{d}}{{{d}{\left(\theta\right)}}}$
(sin(theta))

$\displaystyle={2}{\cot{{\left({\sin{{\left(\theta\right)}}}\right)}}}\cdot{\left(-{{\csc}}^{{2}}{\left({\sin{{\left(\theta\right)}}}\right)}\right)}\cdot{\cos{{\left(\theta\right)}}}$

$\displaystyle=-{2}{\cos{{\left(\theta\right)}}}\cdot{\cot{{\left({\sin{{\left(\theta\right)}}}\right)}}}\cdot{{\csc}}^{{2}}{\left({\sin{{\left(\theta\right)}}}\right)}$

Notes

Monday, 27 June 2016

$\displaystyle{y}={{\cot}}^{{2}}{\left({\sin{{\left(\theta\right)}}}\right)}$ Find the derivative of the function.

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