Monday 27 June 2016

`y = cot^2(sin( theta))` Find the derivative of the function.

`y' =
d/(d(theta))cot^2(sin(theta))`

`= 2 cot (sin(theta)) * d/(d(theta))
[cot(sin(theta))]`

`= 2cot(sin(theta))*(-csc^2(sin(theta)))*d/(d(theta))
(sin(theta))`

`= 2 cot(sin(theta))*(-csc^2(sin(theta)))*cos(theta)`


`= -2 cos(theta)*cot(sin(theta))*csc^2(sin(theta))`

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