`int_-1^2(1-x)dx`
To
interpret the integral in terms of area , graph the integrand.
The integrand
is the function `f(x)=1-x`
Graph the function in the interval (-1,2). Refer
the attached graph.
The bounded region forms two triangles, one triangle
below the x-axis and second triangle above the x-axis.
Area of triangle above
the x-axis `A_2=1/2b_2h_2`
`A_2=1/2*2*2=2`
Area of
triangle below the x-axis `A_1=1/2b_1h_1`
`A_1=1/2*1*1=1/2`
So,`int_-1^2(1-x)dx=A_2-A_1`
`=2-1/2`
`=3/2`
Images:
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