A 15.00 mL sample of NaOH was titrated to the stoichiometric point with 17.40 mL of 0.2340 M HCl. What is the molar concentration of the NaOH solution?

First, we
need to write the chemical equation for this reaction:

`NaOH + HCl -> NaCl
+ H_2O`

Looking at the balanced chemical equation we can see that there is
1:1 ration between the two reactants. Therefore:

`Mol es HCl = Mol es
NaOH`

To determine the molar concentration of the NaOH solution, first we
need to get the moles of HCl.

`Mol es HCl = (17.40)/(1000) L * 0.2340 M =
0.0040716 mol es HCl`

Since we know that moles of HCl are equal to the moles
of NaOH, therefore:

moles HCl = moles NaOH
= 0.0040716

 

`Molarity of NaOH
= (mol es NaOH)/(volume of solution (L))`

`Molarity of NaOH =
(0.0040716)/(0.015)`

Molarity of NaOH = 0.2714
M

href="https://en.wikipedia.org/wiki/Molar_concentration">https://en.wikipedia.org/wiki/Molar_concentration
href="https://en.wikipedia.org/wiki/Stoichiometry">https://en.wikipedia.org/wiki/Stoichiometry