A 15.00 mL sample of NaOH was titrated to the stoichiometric point with 17.40 mL of 0.2340 M HCl. What is the molar concentration of the NaOH solution?

First, we
need to write the chemical equation for this reaction:

+ H_2O

Looking at the balanced chemical equation we can see that there is
1:1 ration between the two reactants. Therefore:

NaOH

To determine the molar concentration of the NaOH solution, first we
need to get the moles of HCl.

0.0040716 mol es HCl

Since we know that moles of HCl are equal to the moles
of NaOH, therefore:

moles HCl = moles NaOH
= 0.0040716

 

= (mol es NaOH)/(volume of solution (L))

(0.0040716)/(0.015)

Molarity of NaOH = 0.2714
M

href="https://en.wikipedia.org/wiki/Molar_concentration">https://en.wikipedia.org/wiki/Molar_concentration
href="https://en.wikipedia.org/wiki/Stoichiometry">https://en.wikipedia.org/wiki/Stoichiometry