We can use
the combine gas law to solve this problem. It is expressed as:
`(P_1
V_1)/(T_1) = (P_2 V_2)/(T_2)`
- P1 = 120kPa = 1.1844 atm
- V1 = 62 mL = 0.062L
- T1 = 373
- P2 = 80 kPa...
Tuesday, 30 August 2016
What is the new Kelvin temperature of a gas if originally 62.0 ml of the gas was at a temperature of 373 K and a pressure of 120 KPA and the volume...
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